javascript - What do curly braces inside of function parameter lists do in es6? - Stack Overflow

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I keep seeing functions that look like this in a codebase I'm working on:

const func = ({ param1, param2 }) => {
  //do stuff
}

What exactly is this doing? I'm having a hard time finding it on google, because I'm not even sure what this is called, or how to describe it in a google search.

I keep seeing functions that look like this in a codebase I'm working on:

const func = ({ param1, param2 }) => {
  //do stuff
}

What exactly is this doing? I'm having a hard time finding it on google, because I'm not even sure what this is called, or how to describe it in a google search.

• javascript
• ecmascript-6

Share Improve this question Follow edited Jun 16, 2019 at 18:36 Bergi 663k158158 gold badges1k1k silver badges1.5k1.5k bronze badges asked Jun 6, 2016 at 15:24 NathanNathan 2,37733 gold badges1616 silver badges1919 bronze badges 1

• possible duplicate of object parameter syntax for javascript functions? – Bergi Commented Jun 16, 2019 at 18:35

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3 Answers 3

Sorted by: Reset to default 181

It is destructuring, but contained within the parameters. The equivalent without the destructuring would be:

const func = o => {
    var param1 = o.param1;
    var param2 = o.param2;
    //do stuff
}

This is passing an object as a property.

It is basically shorthand for

let param1 = someObject.param1
let param2 = someObject.param2

Another way of using this technique without parameters is the following, let's consider then for a second that someObject does contain those properties.

let {param1, param2} = someObject;

It is an object destructuring assignment. Like me, you may have found it surprising because ES6 object destructuring syntax looks like, but does NOT behave like object literal construction.

It supports the very terse form you ran into, as well as renaming the fields and default arguments:

Essentially, it's {oldkeyname:newkeyname=defaultvalue,...}. ':' is NOT the key/value separator; '=' is.

Some fallout of this language design decision is that you might have to do things like

;({a,b}=some_object);

The extra parens prevent the left curly braces parsing as a block, and the leading semicolon prevents the parens from getting parsed as a function call to a function on the previous line.

For more info see: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Destructuring_assignment

Beware, key errors during object destructuring assignment do NOT throw; you just end up with "undefined" values, whether it's a key error or some other error that got silently propagated as 'undefined'.

> var {rsienstr: foo, q: bar} = {p:1, q:undefined};
undefined
> foo
undefined
> bar
undefined
> 

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