javascript - In jQuery, how do I get the value of a radio button when they all have the same name? - Stack Overflow

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Here is my code:

<table>
   <tr>
      <td>Sales Promotion</td>
      <td><input type="radio" name="q12_3" value="1">1</td>
      <td><input type="radio" name="q12_3" value="2">2</td>
      <td><input type="radio" name="q12_3" value="3">3</td>
      <td><input type="radio" name="q12_3" value="4">4</td>
      <td><input type="radio" name="q12_3" value="5">5</td>
   </tr>
</table>
<button id="submit">submit</button>

Here is JS:

$(function(){
    $("#submit").click(function(){      
        alert($('input[name=q12_3]').val());
    });
 });

Here is JSFIDDLE! Every time I click button it returns 1. Why? Can anyone help me?

Here is my code:

<table>
   <tr>
      <td>Sales Promotion</td>
      <td><input type="radio" name="q12_3" value="1">1</td>
      <td><input type="radio" name="q12_3" value="2">2</td>
      <td><input type="radio" name="q12_3" value="3">3</td>
      <td><input type="radio" name="q12_3" value="4">4</td>
      <td><input type="radio" name="q12_3" value="5">5</td>
   </tr>
</table>
<button id="submit">submit</button>

Here is JS:

$(function(){
    $("#submit").click(function(){      
        alert($('input[name=q12_3]').val());
    });
 });

Here is JSFIDDLE! Every time I click button it returns 1. Why? Can anyone help me?

• javascript
• jquery

Share Improve this question Follow edited Jun 19, 2015 at 16:42 Beetle 1,9991616 silver badges3333 bronze badges asked Aug 4, 2013 at 13:29 SPGSPG 6,1971414 gold badges5050 silver badges8181 bronze badges 0

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7 Answers 7

Sorted by: Reset to default 229

In your code, jQuery just looks for the first instance of an input with name q12_3, which in this case has a value of 1. You want an input with name q12_3 that is :checked.

$("#submit").click(() => {
  const val = $('input[name=q12_3]:checked').val();
  alert(val);
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<table>
  <tr>
    <td>Sales Promotion</td>
    <td><input type="radio" name="q12_3" value="1">1</td>
    <td><input type="radio" name="q12_3" value="2">2</td>
    <td><input type="radio" name="q12_3" value="3">3</td>
    <td><input type="radio" name="q12_3" value="4">4</td>
    <td><input type="radio" name="q12_3" value="5">5</td>
  </tr>
</table>
<button id="submit">submit</button>

Note that the above code is not the same as using .is(":checked"). jQuery's is() function returns a boolean (true or false) and not (an) element(s).

---

Because this answer keeps getting a lot of attention, I'll also include a vanilla JavaScript snippet.

document.querySelector("#submit").addEventListener("click", () => {
  const val = document.querySelector("input[name=q12_3]:checked").value;
  alert(val);
});

<table>
  <tr>
    <td>Sales Promotion</td>
    <td><input type="radio" name="q12_3" value="1">1</td>
    <td><input type="radio" name="q12_3" value="2">2</td>
    <td><input type="radio" name="q12_3" value="3">3</td>
    <td><input type="radio" name="q12_3" value="4">4</td>
    <td><input type="radio" name="q12_3" value="5">5</td>
  </tr>
</table>
<button id="submit">submit</button>

in your selector, you should also specify that you want the checked radiobutton:

$(function(){
    $("#submit").click(function(){      
        alert($('input[name=q12_3]:checked').val());
    });
 });

You might want to change selector:

$('input[name=q12_3]:checked').val()

There is another way also. Try below code

$(document).ready(function(){

      $("input[name='gender']").on("click", function() {
            alert($(this).val());
        });
});

$('input:radio[name=q12_3]:checked').val();

DEMO : https://jsfiddle.net/ipsjolly/xygr065w/

$(function(){
    $("#submit").click(function(){      
        alert($('input:radio:checked').val());
    });
 });

use this script

$('input[name=q12_3]').is(":checked");

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