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What I'm trying to do is to count all of the elements in the current page with the same class and then I'm going to use it to be added onto a name for an input form. Basically I'm allowing users to click on a <span> and then by doing so add another one for more of the same type of items. But I can't think of a way to count all of these simply with jQuery/JavaScript.

I was going to then name the item as something like name="whatever(total+1)", if anyone has a simple way to do this I'd be extremely grateful as JavaScript isn't exactly my native tongue.

What I'm trying to do is to count all of the elements in the current page with the same class and then I'm going to use it to be added onto a name for an input form. Basically I'm allowing users to click on a <span> and then by doing so add another one for more of the same type of items. But I can't think of a way to count all of these simply with jQuery/JavaScript.

I was going to then name the item as something like name="whatever(total+1)", if anyone has a simple way to do this I'd be extremely grateful as JavaScript isn't exactly my native tongue.

Share Improve this question edited Apr 25, 2019 at 13:30 Kamil Kiełczewski 92.2k34 gold badges394 silver badges370 bronze badges asked Apr 28, 2010 at 6:40 133794m3r133794m3r 5,1183 gold badges25 silver badges37 bronze badges 3
  • 3 the first person i saw got it and i didn't know it was a simple $('.classname').length to get it. If i had more to give i would. Didn't think to try it like that. I've been setting variables quite a bit and simple things like appending documents etc. etc. Wow i feel pretty dumb now i should've thought to look for the .length() command to see what it said... thanks to everyone btw. – 133794m3r Commented Apr 28, 2010 at 7:42
  • 29 +1 For asking a question like Yoda – jbnunn Commented Mar 7, 2012 at 17:14
  • 7 @jbnunn what is Yoda? – shasi kanth Commented Oct 30, 2014 at 6:18
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6 Answers 6

Reset to default 815

Should just be something like:

// Gets the number of elements with class yourClass
var numItems = $('.yourclass').length




As a side-note, it is often beneficial to check the length property before chaining a lot of functions calls on a jQuery object, to ensure that we actually have some work to perform. See below:

var $items = $('.myclass');
// Ensure we have at least one element in $items before setting up animations
// and other resource intensive tasks.
if($items.length)
{
  $items.animate(/* */)
    // It might also be appropriate to check that we have 2 or more
    // elements returned by the filter-call before animating this subset of 
    // items.
    .filter(':odd')
      .animate(/* */)
      .end()
    .promise()
    .then(function () { 
       $items.addClass('all-done');
    });
}

Getting a count of the number of elements that refer to the same class is as simple as this

<html>
    <head>
        <script src="http://code.jquery.com/jquery-1.4.2.min.js"></script>
        <script type="text/javascript">

            $(document).ready(function() {
                alert( $(".red").length );
            });

        </script>
    </head>
    <body>

        <p class="red">Test</p>
        <p class="red">Test</p>
        <p class="red anotherclass">Test</p>
        <p class="red">Test</p>
        <p class="red">Test</p>
        <p class="red anotherclass">Test</p>
    </body>
</html>
var count = $('.' + myclassname).length;

HTML:

<div>
    <img src='' class='class' />
    <img src='' class='class' />
    <img src='' class='class' />
</div>

    

JavaScript:

var numItems = $('.class').length; 
        
alert(numItems);

Fiddle demo for inside only div

for counting:

$('.yourClass').length;

should work fine.

storing in a variable is as easy as:

var count = $('.yourClass').length;

try

document.getElementsByClassName('myclass').length

let num = document.getElementsByClassName('myclass').length;
console.log('Total "myclass" elements: '+num);
.myclass { color: red }
<span class="myclass" >1</span>
<span>2</span>
<span class="myclass">3</span>
<span class="myclass">4</span>

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