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I am working with Javascript(ES6) /FaceBook react and trying to get the first 3 elements of an array that varies in size. I would like do the equivalent of Linq take(n).

In my Jsx file I have the following:

var items = list.map(i => {
  return (
    <myview item={i} key={i.id} />
  );
});

Then to get the first 3 items I tried

  var map = new Map(list);
    map.size = 3;
    var items = map(i => {
      return (<SpotlightLandingGlobalInboxItem item={i} key={i.id} />);
    });

This didn't work as map doesn't have a set function. What can I try next?

I am working with Javascript(ES6) /FaceBook react and trying to get the first 3 elements of an array that varies in size. I would like do the equivalent of Linq take(n).

In my Jsx file I have the following:

var items = list.map(i => {
  return (
    <myview item={i} key={i.id} />
  );
});

Then to get the first 3 items I tried

  var map = new Map(list);
    map.size = 3;
    var items = map(i => {
      return (<SpotlightLandingGlobalInboxItem item={i} key={i.id} />);
    });

This didn't work as map doesn't have a set function. What can I try next?

• javascript
• arrays
• filtering
• slice
• extract

Share Improve this question Follow edited Feb 21, 2023 at 15:16 halfer 20.4k1919 gold badges108108 silver badges201201 bronze badges asked Jan 19, 2016 at 17:19 user1526912user1526912 17.2k1818 gold badges6161 silver badges9797 bronze badges 0

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13 Answers 13

Sorted by: Reset to default 1808

To get the first n elements of an array, use

const slicedArray = array.slice(0, n);

I believe what you're looking for is:

// ...inside the render() function

var size = 3;
var items = list.slice(0, size).map(i => {
    return <myview item={i} key={i.id} />
});                       
return (
  <div>
    {items}
  </div>   
)

arr.length = n

This might be surprising but length property of an array is not only used to get number of array elements but it's also writable and can be used to set array's length MDN link. This will mutate the array.

If you don't care about immutability or don't want to allocate memory i.e. for a game this will be the fastest way.

to empty an array

arr.length = 0

Use Slice Method

The javascript slice() method returns a portion of an array into a new array object selected from start to end where start and end represent the index of items in that array. The original array will not be modified.

syntax : slice(start, end)

Let us say we have an array with 7 items [5,10,15,20,25,30,35] and we want the first 5 elements from that array:

let array = [5,10,15,20,25,30,35]
let newArray = array.slice(0,5)

console.log(newArray)

You can filter using index of array.

var months = ['Jan', 'March', 'April', 'June'];
months = months.filter((month,idx) => idx < 2)
console.log(months);

Do not try doing that using a map function. Map function should be used to map values from one thing to other. When the number of input and output match.

In this case use filter function which is also available on the array. Filter function is used when you want to selectively take values maching certain criteria. Then you can write your code like

var items = list
             .filter((i, index) => (index < 3))
             .map((i, index) => {
                   return (
                     <myview item={i} key={i.id} />
                   );
              });

Just try this to get first n elements from list:

const slicedList = list.slice(0, n);

Example:

const list = [1,2,3,4,5]
console.log(list.slice(0, 3)) // Should return [1,2,3] 
console.log(list.slice(0, 10)) // Returns [1,2,3,4,5] since this is all we have in 1st 10 elements

[1,2,3,4,5,6,7,8,8].slice(0, 3) = While return the first 3 elements.

Answer: [1,2,3]

How it works:

The slice() method returns a shallow copy of a portion of an array into a new array object selected from start to end (end not included) where start and end represent the index of items in that array. The original array will not be modified.

The following worked for me.

array.slice( where_to_start_deleting, array.length )

Here is an example

var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.slice(2, fruits.length);
//Banana,Orange  ->These first two we get as resultant

With lodash, take function, you can achieve this by following:

_.take([1, 2, 3]);
// => [1]
 
_.take([1, 2, 3], 2);
// => [1, 2]
 
_.take([1, 2, 3], 5);
// => [1, 2, 3]
 
_.take([1, 2, 3], 0);
// => []

Using a simple example:

var letters = ["a", "b", "c", "d"];
var letters_02 = letters.slice(0, 2);
console.log(letters_02)

Output: ["a", "b"]

var letters_12 = letters.slice(1, 2);
console.log(letters_12)

Output: ["b"]

Note: slice provides only a shallow copy and DOES NOT modify the original array.

The slice() method returns a shallow copy of a portion of an array into a new array object selected from start to end (end not included) where start and end represent the index of items in that array. The original array will not be modified.

const animals = ['ant', 'bison', 'camel', 'duck', 'elephant'];

console.log(animals.slice(2));
// expected output: Array ["camel", "duck", "elephant"]

console.log(animals.slice(2, 4));
// expected output: Array ["camel", "duck"]

console.log(animals.slice(1, 5));
// expected output: Array ["bison", "camel", "duck", "elephant"]

console.log(animals.slice(-2));
// expected output: Array ["duck", "elephant"]

console.log(animals.slice(2, -1));
// expected output: Array ["camel", "duck"]

know more

With LInQer you can do:

Enumerable.from(list).take(3).toArray();

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