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I have been reading online and some places say it isn't possible, some say it is and then give an example and others refute the example, etc.
How do I declare a 2 dimensional array in JavaScript? (assuming it's possible)
How would I access its members? (
myArray[0][1]ormyArray[0,1]?)
I have been reading online and some places say it isn't possible, some say it is and then give an example and others refute the example, etc.
How do I declare a 2 dimensional array in JavaScript? (assuming it's possible)
How would I access its members? (
myArray[0][1]ormyArray[0,1]?)
56 Answers
Reset to default 1 2 Next 1425Practically? Yes. You can create an array of arrays which functions as an 2D array as every item is an array itself:
let items = [
[1, 2],
[3, 4],
[5, 6]
];
console.log(items[0][0]); // 1
console.log(items[0][1]); // 2
console.log(items[1][0]); // 3
console.log(items[1][1]); // 4
console.log(items);But technically this is just an array of arrays and not a “true” 2D array, as I. J. Kennedy pointed out.
It should be noted that you could keep nesting arrays into one another and so create “multidimensional” arrays.
You simply make each item within the array an array.
var x = new Array(10);
for (var i = 0; i < x.length; i++) {
x[i] = new Array(3);
}
console.log(x);How to create an empty two dimensional array (one-line)
Array.from(Array(2), () => new Array(4))
2 and 4 being first and second dimensions respectively.
We are making use of Array.from, which can take an array-like param and an optional mapping for each of the elements.
Array.from(arrayLike[, mapFn[, thisArg]])
var arr = Array.from(Array(2), () => new Array(4));
arr[0][0] = 'foo';
console.info(arr);The same trick can be used to Create a JavaScript array containing 1...N
Alternatively (but more inefficient 12% with n = 10,000)
Array(2).fill(null).map(() => Array(4))
The performance decrease comes with the fact that we have to have the first dimension values initialized to run .map. Remember that Array will not allocate the positions until you order it to through .fill or direct value assignment.
var arr = Array(2).fill(null).map(() => Array(4));
arr[0][0] = 'foo';
console.info(arr);Follow up
Here's a method that appears correct, but has issues.
Array(2).fill(Array(4)); // BAD! Rows are copied by reference
While it does return the apparently desired two dimensional array ([ [ <4 empty items> ], [ <4 empty items> ] ]), there a catch: first dimension arrays have been copied by reference. That means a arr[0][0] = 'foo' would actually change two rows instead of one.
var arr = Array(2).fill(Array(4));
arr[0][0] = 'foo';
console.info(arr);
console.info(arr[0][0], arr[1][0]);Similar to activa's answer, here's a function to create an n-dimensional array:
function createArray(length) {
var arr = new Array(length || 0),
i = length;
if (arguments.length > 1) {
var args = Array.prototype.slice.call(arguments, 1);
while(i--) arr[length-1 - i] = createArray.apply(this, args);
}
return arr;
}
createArray(); // [] or new Array()
createArray(2); // new Array(2)
createArray(3, 2); // [new Array(2),
// new Array(2),
// new Array(2)]
Javascript only has 1-dimensional arrays, but you can build arrays of arrays, as others pointed out.
The following function can be used to construct a 2-d array of fixed dimensions:
function Create2DArray(rows) {
var arr = [];
for (var i=0;i<rows;i++) {
arr[i] = [];
}
return arr;
}
The number of columns is not really important, because it is not required to specify the size of an array before using it.
Then you can just call:
var arr = Create2DArray(100);
arr[50][2] = 5;
arr[70][5] = 7454;
// ...
The easiest way:
var myArray = [[]];
The reason some say that it isn't possible is because a two dimensional array is really just an array of arrays. The other comments here provide perfectly valid methods of creating two dimensional arrays in JavaScript, but the purest point of view would be that you have a one dimensional array of objects, each of those objects would be a one dimensional array consisting of two elements.
So, that's the cause of the conflicting view points.
Few people show the use of push:
To bring something new, I will show you how to initialize the matrix with some value, example: 0 or an empty string "".
Reminding that if you have a 10 elements array, in javascript the last index will be 9!
function matrix( rows, cols, defaultValue){
var arr = [];
// Creates all lines:
for(var i=0; i < rows; i++){
// Creates an empty line
arr.push([]);
// Adds cols to the empty line:
arr[i].push( new Array(cols));
for(var j=0; j < cols; j++){
// Initializes:
arr[i][j] = defaultValue;
}
}
return arr;
}
usage examples:
x = matrix( 2 , 3,''); // 2 lines, 3 cols filled with empty string
y = matrix( 10, 5, 0);// 10 lines, 5 cols filled with 0
Two-liner:
var a = [];
while(a.push([]) < 10);
It will generate an array a of the length 10, filled with arrays. (Push adds an element to an array and returns the new length)
The sanest answer seems to be
var nrows = ~~(Math.random() * 10);
var ncols = ~~(Math.random() * 10);
console.log(`rows:${nrows}`);
console.log(`cols:${ncols}`);
var matrix = new Array(nrows).fill(0).map(row => new Array(ncols).fill(0));
console.log(matrix);Note we can't directly fill with the rows since fill uses shallow copy constructor, therefore all rows would share the same memory...here is example which demonstrates how each row would be shared (taken from other answers):
// DON'T do this: each row in arr, is shared
var arr = Array(2).fill(Array(4));
arr[0][0] = 'foo'; // also modifies arr[1][0]
console.info(arr);
The easiest way:
var arr = [];
var arr1 = ['00','01'];
var arr2 = ['10','11'];
var arr3 = ['20','21'];
arr.push(arr1);
arr.push(arr2);
arr.push(arr3);
alert(arr[0][1]); // '01'
alert(arr[1][1]); // '11'
alert(arr[2][0]); // '20'
Performance
Today 2020.02.05 I perform tests on MacOs HighSierra 10.13.6 on Chrome v79.0, Safari v13.0.4 and Firefox v72.0, for chosen solutions.
Conclusions for non-initialised 2d array
- esoteric solution
{}/arr[[i,j]](N) is fastest for big and small arrays and it looks like it is good choice for big sparse arrays - solutions based on
for-[]/while(A,G) are fast and they are good choice for small arrays. - solutions
for-[](B,C) are fast and they are good choice for big arrays - solutions based on
Array..map/from/fill(I,J,K,L,M) are quite slow for small arrays, and quite fast for big arrays - surprinsingly
for-Array(n)(B,C) is much slower on safari thanfor-[](A) - surprinsingly
for-[](A) for big array is slow on all browsers - solutions K is slow for small arrays for all browsers
- solutions A,E,G are slow for big arrays for all browsers
- solution M is slowest for all arrays on all browsers
Conclusions for initialised 2d array
- solutions based on
for/while(A,B,C,D,E,G) are fastest/quite fast for small arrays on all browsers - solutions based on
for(A,B,C,E) are fastest/quite fast for big arrays on all browsers - solutions based on
Array..map/from/fill(I,J,K,L,M) are medium fast or slow for small arrays on all browsers - solutions F,G,H,I,J,K,L for big arrays are medium or fast on chrome and safari but slowest on firefox.
- esoteric solution
{}/arr[[i,j]](N) is slowest for small and big arrays on all browsers
Details
Test for solutions which not fill (initialise) output array
We test speed of solutions for
- small arrays (12 elements) - you can perform tests on your machine HERE
- big arrays (1 million elements) arrays - you can perform tests on your machine HERE
function A(r) {
var arr = [];
for (var i = 0; i < r; i++) arr[i] = [];
return arr;
}
function B(r, c) {
var arr = new Array(r);
for (var i = 0; i < arr.length; i++) arr[i] = new Array(c);
return arr;
}
function C(r, c) {
var arr = Array(r);
for (var i = 0; i < arr.length; i++) arr[i] = Array(c);
return arr;
}
function D(r, c) {
// strange, but works
var arr = [];
for (var i = 0; i < r; i++) {
arr.push([]);
arr[i].push(Array(c));
}
return arr;
}
function E(r, c) {
let array = [[]];
for (var x = 0; x < c; x++) {
array[x] = [];
for (var y = 0; y < r; y++) array[x][y] = [0];
}
return array;
}
function F(r, c) {
var makeArray = function(dims, arr) {
if (dims[1] === undefined) {
return Array(dims[0]);
}
arr = Array(dims[0]);
for (var i = 0; i < dims[0]; i++) {
arr[i] = Array(dims[1]);
arr[i] = makeArray(dims.slice(1), arr[i]);
}
return arr;
}
return makeArray([r, c]);
}
function G(r) {
var a = [];
while (a.push([]) < r);
return a;
}
function H(r,c) {
function createArray(length) {
var arr = new Array(length || 0),
i = length;
if (arguments.length > 1) {
var args = Array.prototype.slice.call(arguments, 1);
while(i--) arr[length-1 - i] = createArray.apply(this, args);
}
return arr;
}
return createArray(r,c);
}
function I(r, c) {
return [...Array(r)].map(x => Array(c));
}
function J(r, c) {
return Array(r).fill(0).map(() => Array(c));
}
function K(r, c) {
return Array.from(Array(r), () => Array(c));
}
function L(r, c) {
return Array.from({length: r}).map(e => Array(c));
}
function M(r, c) {
return Array.from({length: r}, () => Array.from({length: c}, () => {}));
}
function N(r, c) {
return {}
}
// -----------------------------------------------
// SHOW
// -----------------------------------------------
log = (t, f) => {
let A = f(3, 4); // create array with 3 rows and 4 columns
A[1][2] = 6 // 2-nd row 3nd column set to 6
console.log(`${t}[1][2]: ${A[1][2]}, full: ${JSON.stringify(A).replace(/null/g,'x')}`);
}
log2 = (t, f) => {
let A = f(3, 4); // create array with 3 rows and 4 columns
A[[1,2]] = 6 // 2-nd row 3nd column set to 6
console.log(`${t}[1][2]: ${A[[1,2]]}, full: ${JSON.stringify(A).replace(/null/g,'x')}`);
}
log('A', A);
log('B', B);
log('C', C);
log('D', D);
log('E', E);
log('F', F);
log('G', G);
log('H', H);
log('I', I);
log('J', J);
log('K', K);
log('L', L);
log('M', M);
log2('N', N);This is presentation of solutions - not benchmarkTest for solutions which fill (initialise) output array
We test speed of solutions for
- small arrays (12 elements) - you can perform tests on your machine HERE
- big arrays (1 million elements) arrays - you can perform tests on your machine HERE
function A(r, c, def) {
var arr = [];
for (var i = 0; i < r; i++) arr[i] = Array(c).fill(def);
return arr;
}
function B(r, c, def) {
var arr = new Array(r);
for (var i = 0; i < arr.length; i++) arr[i] = new Array(c).fill(def);
return arr;
}
function C(r, c, def) {
var arr = Array(r);
for (var i = 0; i < arr.length; i++) arr[i] = Array(c).fill(def);
return arr;
}
function D(r, c, def) {
// strange, but works
var arr = [];
for (var i = 0; i < r; i++) {
arr.push([]);
arr[i].push(Array(c));
}
for (var i = 0; i < r; i++) for (var j = 0; j < c; j++) arr[i][j]=def
return arr;
}
function E(r, c, def) {
let array = [[]];
for (var x = 0; x < c; x++) {
array[x] = [];
for (var y = 0; y < r; y++) array[x][y] = def;
}
return array;
}
function F(r, c, def) {
var makeArray = function(dims, arr) {
if (dims[1] === undefined) {
return Array(dims[0]).fill(def);
}
arr = Array(dims[0]);
for (var i = 0; i < dims[0]; i++) {
arr[i] = Array(dims[1]);
arr[i] = makeArray(dims.slice(1), arr[i]);
}
return arr;
}
return makeArray([r, c]);
}
function G(r, c, def) {
var a = [];
while (a.push(Array(c).fill(def)) < r);
return a;
}
function H(r,c, def) {
function createArray(length) {
var arr = new Array(length || 0),
i = length;
if (arguments.length > 1) {
var args = Array.prototype.slice.call(arguments, 1);
while(i--) arr[length-1 - i] = createArray.apply(this, args).fill(def);
}
return arr;
}
return createArray(r,c);
}
function I(r, c, def) {
return [...Array(r)].map(x => Array(c).fill(def));
}
function J(r, c, def) {
return Array(r).fill(0).map(() => Array(c).fill(def));
}
function K(r, c, def) {
return Array.from(Array(r), () => Array(c).fill(def));
}
function L(r, c, def) {
return Array.from({length: r}).map(e => Array(c).fill(def));
}
function M(r, c, def) {
return Array.from({length: r}, () => Array.from({length: c}, () => def));
}
function N(r, c, def) {
let arr={};
for (var i = 0; i < r; i++) for (var j = 0; j < c; j++) arr[[i,j]]=def;
return arr;
}
// -----------------------------------------------
// SHOW
// -----------------------------------------------
log = (t, f) => {
let A = f(1000,1000,7); // create array with 1000 rows and 1000 columns,
// each array cell initilised by 7
A[800][900] = 5 // 800nd row and 901nd column set to 5
console.log(`${t}[1][2]: ${A[1][2]}, ${t}[800][901]: ${A[800][900]}`);
}
log2 = (t, f) => {
let A = f(1000,1000,7); // create array with 1000 rows and 1000 columns,
// each array cell initilised by 7
A[[800,900]] = 5 // 800nd row 900nd column set to 5
console.log(`${t}[1][2]: ${A[[1,2]]}, ${t}[800][900]: ${A[[800,900]]}`);
}
log('A', A);
log('B', B);
log('C', C);
log('D', D);
log('E', E);
log('F', F);
log('G', G);
log('H', H);
log('I', I);
log('J', J);
log('K', K);
log('L', L);
log('M', M);
log2('N', N);This is presentation of solutions - not benchmarkTo create an 4x6 array, simply do this
const x = [...new Array(6)].map(elem => new Array(4))
It's usually a good practice to start with an empty array, rather than filling w random values. (You normally declare array as const x = [] in 1D, so better to start w empty in 2D.)
This is what i achieved :
var appVar = [[]];
appVar[0][4] = "bineesh";
appVar[0][5] = "kumar";
console.log(appVar[0][4] + appVar[0][5]);
console.log(appVar);This spelled me bineeshkumar
Two dimensional arrays are created the same way single dimensional arrays are. And you access them like array[0][1].
var arr = [1, 2, [3, 4], 5];
alert (arr[2][1]); //alerts "4"
For one liner lovers Array.from()
// creates 8x8 array filed with "0"
const arr2d = Array.from({ length: 8 }, () => Array.from({ length: 8 }, () => "0"))
Another one (from comment by dmitry_romanov) use Array().fill()
// creates 8x8 array filed with "0"
const arr2d = Array(8).fill(0).map(() => Array(8).fill("0"))
Using ES6+ spread operator ("inspired" by InspiredJW answer :) )
// same as above just a little shorter
const arr2d = [...Array(8)].map(() => Array(8).fill("0"))
I'm not sure if anyone has answered this but I found this worked for me pretty well -
var array = [[,],[,]]
eg:
var a = [[1,2],[3,4]]
For a 2 dimensional array, for instance.
To create a non-sparse "2D" array (x,y) with all indices addressable and values set to null:
let 2Darray = new Array(x).fill(null).map(item =>(new Array(y).fill(null)))
bonus "3D" Array (x,y,z)
let 3Darray = new Array(x).fill(null).map(item=>(new Array(y).fill(null)).map(item=>Array(z).fill(null)))
Variations and corrections on this have been mentioned in comments and at various points in response to this question but not as an actual answer so I am adding it here.
It should be noted that (similar to most other answers) this has O(x*y) time complexity so it probably not suitable for very large arrays.
To create a 2D array in javaScript we can create an Array first and then add Arrays as it's elements. This method will return a 2D array with the given number of rows and columns.
function Create2DArray(rows,columns) {
var x = new Array(rows);
for (var i = 0; i < rows; i++) {
x[i] = new Array(columns);
}
return x;
}
to create an Array use this method as below.
var array = Create2DArray(10,20);
Use Array Comprehensions
In JavaScript 1.7 and higher you can use array comprehensions to create two dimensional arrays. You can also filter and/or manipulate the entries while filling the array and don't have to use loops.
var rows = [1, 2, 3];
var cols = ["a", "b", "c", "d"];
var grid = [ for (r of rows) [ for (c of cols) r+c ] ];
/*
grid = [
["1a","1b","1c","1d"],
["2a","2b","2c","2d"],
["3a","3b","3c","3d"]
]
*/
You can create any n x m array you want and fill it with a default value by calling
var default = 0; // your 2d array will be filled with this value
var n_dim = 2;
var m_dim = 7;
var arr = [ for (n of Array(n_dim)) [ for (m of Array(m_dim) default ]]
/*
arr = [
[0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0],
]
*/
More examples and documentation can be found here.
Please note that this is not a standard feature yet.
Row and Column sizes of an array known only at the run time then following method could be used for creating a dynamic 2d array.
var num = '123456';
var row = 3; // Known at run time
var col = 2; // Known at run time
var i = 0;
var array2D = [[]];
for(var r = 0; r < row; ++r)
{
array2D[r] = [];
for(var c = 0; c < col; ++c)
{
array2D[r][c] = num[i++];
}
}
console.log(array2D);
// [[ '1', '2' ],
// [ '3', '4' ],
// [ '5', '6' ]]
console.log(array2D[2][1]); // 6Array(m).fill(v).map(() => Array(n).fill(v))
You can create a 2 Dimensional array m x n with initial value m and n can be any numbers v can be any value string, number, undefined.
One approach can be var a = [m][n]
The following example defines a two-dimensional array named activities:
let activities = [
['Work', 9],
['Eat', 1],
['Commute', 2],
['Play Game', 1],
['Sleep', 7]
];
In the activities array, the first dimension represents the activity and the second one shows the number of hours spent per day for each.
To show the activities array in the console, you use the console.table() method as follows:
console.table(activities);
The following illustrates the output:
┌─────────┬─────────────┬───┐ │ (index) │ 0 │ 1 │ ├─────────┼─────────────┼───┤ │ 0 │ 'Work' │ 9 │ │ 1 │ 'Eat' │ 1 │ │ 2 │ 'Commute' │ 2 │ │ 3 │ 'Play Game' │ 1 │ │ 4 │ 'Sleep' │ 7 │ └─────────┴─────────────┴───┘
Note that the (index) column is for the illustration that indicates the indices of the inner array.
To access an element of the multidimensional array, you first use square brackets to access an element of the outer array that returns an inner array; and then use another square bracket to access the element of the inner array.
The following example returns the second element of the first inner array in the activities array above:
console.log(activities[0][1]); // 9
Adding elements to the JavaScript multidimensional array
You can use the Array methods such as push() and splice() to manipulate elements of a multidimensional array.
For example, to add a new element at the end of the multidimensional array, you use the push() method as follows:
activities.push(['Study',2]);
┌─────────┬─────────────┬───┐ │ (index) │ 0 │ 1 │ ├─────────┼─────────────┼───┤ │ 0 │ 'Work' │ 9 │ │ 1 │ 'Eat' │ 1 │ │ 2 │ 'Commute' │ 2 │ │ 3 │ 'Play Game' │ 1 │ │ 4 │ 'Sleep' │ 7 │ │ 5 │ 'Study' │ 2 │ └─────────┴─────────────┴───┘
To insert an element in the middle of the array, you use the splice() method. The following inserts an element in the second position of the activities array:
activities.splice(1, 0, ['Programming', 2]);
┌─────────┬───────────────┬───┐ │ (index) │ 0 │ 1 │ ├─────────┼───────────────┼───┤ │ 0 │ 'Work' │ 9 │ │ 1 │ 'Programming' │ 2 │ │ 2 │ 'Eat' │ 1 │ │ 3 │ 'Commute' │ 2 │ │ 4 │ 'Play Game' │ 1 │ │ 5 │ 'Sleep' │ 7 │ │ 6 │ 'Study' │ 2 │ └─────────┴───────────────┴───┘
This example calculates the percentage of the hours spent on each activity and appends the percentage to the inner array.
activities.forEach(activity => {
let percentage = ((activity[1] / 24) * 100).toFixed();
activity[2] = percentage + '%';
});
┌─────────┬───────────────┬───┬───────┐ │ (index) │ 0 │ 1 │ 2 │ ├─────────┼───────────────┼───┼───────┤ │ 0 │ 'Work' │ 9 │ '38%' │ │ 1 │ 'Programming' │ 2 │ '8%' │ │ 2 │ 'Eat' │ 1 │ '4%' │ │ 3 │ 'Commute' │ 2 │ '8%' │ │ 4 │ 'Play Game' │ 1 │ '4%' │ │ 5 │ 'Sleep' │ 7 │ '29%' │ │ 6 │ 'Study' │ 2 │ '8%' │ └─────────┴───────────────┴───┴───────┘
Removing elements from the JavaScript multidimensional array
To remove an element from an array, you use the pop() or splice() method.
For example, the following statement removes the last element of the activities array:
activities.pop();
┌─────────┬───────────────┬───┬───────┐ │ (index) │ 0 │ 1 │ 2 │ ├─────────┼───────────────┼───┼───────┤ │ 0 │ 'Work' │ 9 │ '38%' │ │ 1 │ 'Programming' │ 2 │ '8%' │ │ 2 │ 'Eat' │ 1 │ '4%' │ │ 3 │ 'Commute' │ 2 │ '8%' │ │ 4 │ 'Play Game' │ 1 │ '4%' │ │ 5 │ 'Sleep' │ 7 │ '29%' │ └─────────┴───────────────┴───┴───────┘
Similarly, you can remove the elements from the inner array of the multidimensional array by using the pop() method. The following example removes the percentage element from the inner arrays of the activities array.
activities.forEach((activity) => {
activity.pop(2);
});
┌─────────┬───────────────┬───┐ │ (index) │ 0 │ 1 │ ├─────────┼───────────────┼───┤ │ 0 │ 'Work' │ 9 │ │ 1 │ 'Programming' │ 2 │ │ 2 │ 'Eat' │ 1 │ │ 3 │ 'Commute' │ 2 │ │ 4 │ 'Play Game' │ 1 │ │ 5 │ 'Sleep' │ 7 │ └─────────┴───────────────┴───┘
Iterating over elements of the JavaScript multidimensional array
To iterate a multidimensional array, you use a nested for loop as in the following example.
// loop the outer array
for (let i = 0; i < activities.length; i++) {
// get the size of the inner array
var innerArrayLength = activities[i].length;
// loop the inner array
for (let j = 0; j < innerArrayLength; j++) {
console.log('[' + i + ',' + j + '] = ' + activities[i][j]);
}
}
The first loop iterates over the elements of the outer array and the nested loop iterates over elements of the inner array.
The following shows the output of the script in the console:
[0,0] = Work [0,1] = 9 [1,0] = Eat [1,1] = 1 [2,0] = Commute [2,1] = 2 [3,0] = Play Game [3,1] = 1 [4,0] = Sleep [4,1] = 7 [5,0] = Study [5,1] = 2
Or you can use the forEach() method twice:
activities.forEach((activity) => {
activity.forEach((data) => {
console.log(data);
});
});
Work 9 Eat 1 Commute 2 Play Game 1 Sleep 7 Study 2
My approach is very similar to @Bineesh answer but with a more general approach.
You can declare the double array as follows:
var myDoubleArray = [[]];
And the storing and accessing the contents in the following manner:
var testArray1 = [9,8]
var testArray2 = [3,5,7,9,10]
var testArray3 = {"test":123}
var index = 0;
myDoubleArray[index++] = testArray1;
myDoubleArray[index++] = testArray2;
myDoubleArray[index++] = testArray3;
console.log(myDoubleArray[0],myDoubleArray[1][3], myDoubleArray[2]['test'],)
This will print the expected output
[ 9, 8 ] 9 123
I found below is the simplest way:
var array1 = [[]];
array1[0][100] = 5;
alert(array1[0][100]);
alert(array1.length);
alert(array1[0].length);
var playList = [
['I Did It My Way', 'Frank Sinatra'],
['Respect', 'Aretha Franklin'],
['Imagine', 'John Lennon'],
['Born to Run', 'Bruce Springsteen'],
['Louie Louie', 'The Kingsmen'],
['Maybellene', 'Chuck Berry']
];
function print(message) {
document.write(message);
}
function printSongs( songs ) {
var listHTML;
listHTML = '<ol>';
for ( var i = 0; i < songs.length; i += 1) {
listHTML += '<li>' + songs[i][0] + ' by ' + songs[i][1] + '</li>';
}
listHTML += '</ol>';
print(listHTML);
}
printSongs(playList);Below one, creates a 5x5 matrix and fill them with null
var md = [];
for(var i=0; i<5; i++) {
md.push(new Array(5).fill(null));
}
console.log(md);ES6+, ES2015+ can do this in even simpler way
Creating 3 x 2 Array filled with true
[...Array(3)].map(item => Array(2).fill(true))
I had to make a flexible array function to add "records" to it as i needed and to be able to update them and do whatever calculations e needed before i sent it to a database for further processing. Here's the code, hope it helps :).
function Add2List(clmn1, clmn2, clmn3) {
aColumns.push(clmn1,clmn2,clmn3); // Creates array with "record"
aLine.splice(aPos, 0,aColumns); // Inserts new "record" at position aPos in main array
aColumns = []; // Resets temporary array
aPos++ // Increments position not to overlap previous "records"
}
Feel free to optimize and / or point out any bugs :)
Javascript does not support two dimensional arrays, instead we store an array inside another array and fetch the data from that array depending on what position of that array you want to access. Remember array numeration starts at ZERO.
Code Example:
/* Two dimensional array that's 5 x 5
C0 C1 C2 C3 C4
R0[1][1][1][1][1]
R1[1][1][1][1][1]
R2[1][1][1][1][1]
R3[1][1][1][1][1]
R4[1][1][1][1][1]
*/
var row0 = [1,1,1,1,1],
row1 = [1,1,1,1,1],
row2 = [1,1,1,1,1],
row3 = [1,1,1,1,1],
row4 = [1,1,1,1,1];
var table = [row0,row1,row2,row3,row4];
console.log(table[0][0]); // Get the first item in the array
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var arr2D = new Array(5).fill(new Array(3));, each element of Array(5) will point to the same Array(3). So it's best to use a for loop to dynamically populate sub arrays. – Josh Stribling Commented May 23, 2016 at 8:51a = Array(5).fill(0).map(x => Array(10).fill(0))– Longfei Wu Commented Mar 25, 2017 at 14:21filldoesn't callnew Array(3)for each index of the array being filled, since it's not a lambda expression or anything, such as Longfei Wu's comment above, which initially fills the array with 0's, then uses the map function with a lambda to fill each element with a new array. The fill function simply fills the array with exactly what you tell it to. Does that make sense? For more info on themapfunction, see: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… – Josh Stribling Commented Sep 16, 2017 at 5:38If the new question is a better question or has better answers, then vote to close the old one as a duplicate of the new one.– Adam Commented Aug 14, 2019 at 6:49