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I have two radio buttons and want to post the value of the selected one. How can I get the value with jQuery?
I can get all of them like this:
$("form :radio")
How do I know which one is selected?
I have two radio buttons and want to post the value of the selected one. How can I get the value with jQuery?
I can get all of them like this:
$("form :radio")
How do I know which one is selected?
Share Improve this question edited Jan 10, 2020 at 15:06 juan asked Feb 27, 2009 at 19:53 juanjuan 81.8k52 gold badges164 silver badges198 bronze badges39 Answers
Reset to default 1 2 Next 4306To get the value of the selected radioName
item of a form with id myForm
:
$('input[name=radioName]:checked', '#myForm').val()
Here's an example:
$('#myForm input').on('change', function() {
alert($('input[name=radioName]:checked', '#myForm').val());
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
<fieldset>
<legend>Choose radioName</legend>
<label><input type="radio" name="radioName" value="1" /> 1</label> <br />
<label><input type="radio" name="radioName" value="2" /> 2</label> <br />
<label><input type="radio" name="radioName" value="3" /> 3</label> <br />
</fieldset>
</form>
Use this..
$("#myform input[type='radio']:checked").val();
If you already have a reference to a radio button group, for example:
var myRadio = $("input[name=myRadio]");
Use the filter()
function, not find()
. (find()
is for locating child/descendant elements, whereas filter()
searches top-level elements in your selection.)
var checkedValue = myRadio.filter(":checked").val();
Notes: This answer was originally correcting another answer that recommended using find()
, which seems to have since been changed. find()
could still be useful for the situation where you already had a reference to a container element, but not to the radio buttons, e.g.:
var form = $("#mainForm");
...
var checkedValue = form.find("input[name=myRadio]:checked").val();
This should work:
$("input[name='radioName']:checked").val()
Note the "" usaged around the input:checked and not '' like the Peter J's solution
You can use the :checked selector along with the radio selector.
$("form:radio:checked").val();
If you want just the boolean value, i.e. if it's checked or not try this:
$("#Myradio").is(":checked")
Get all radios:
var radios = jQuery("input[type='radio']");
Filter to get the one thats checked
radios.filter(":checked")
Another option is:
$('input[name=radioName]:checked').val()
$("input:radio:checked").val();
In my case I have two radio buttons in one form and I wanted to know the status of each button. This below worked for me:
// get radio buttons value
console.log( "radio1: " + $('input[id=radio1]:checked', '#toggle-form').val() );
console.log( "radio2: " + $('input[id=radio2]:checked', '#toggle-form').val() );
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="toggle-form">
<div id="radio">
<input type="radio" id="radio1" name="radio" checked="checked" /><label for="radio1">Plot single</label>
<input type="radio" id="radio2" name="radio"/><label for="radio2">Plot all</label>
</div>
</form>
Here's how I would write the form and handle the getting of the checked radio.
Using a form called myForm:
<form id='myForm'>
<input type='radio' name='radio1' class='radio1' value='val1' />
<input type='radio' name='radio1' class='radio1' value='val2' />
...
</form>
Get the value from the form:
$('#myForm .radio1:checked').val();
If you're not posting the form, I would simplify it further by using:
<input type='radio' class='radio1' value='val1' />
<input type='radio' class='radio1' value='val2' />
Then getting the checked value becomes:
$('.radio1:checked').val();
Having a class name on the input allows me to easily style the inputs...
try this one. it worked for me
$('input[type="radio"][name="name"]:checked').val();
In a JSF generated radio button (using <h:selectOneRadio>
tag), you can do this:
radiobuttonvalue = jQuery("input[name='form_id\:radiobutton_id']:checked").val();
where selectOneRadio ID is radiobutton_id and form ID is form_id.
Be sure to use name instead id, as indicated, because jQuery uses this attribute (name is generated automatically by JSF resembling control ID).
Also, check if the user does not select anything.
var radioanswer = 'none';
if ($('input[name=myRadio]:checked').val() != null) {
radioanswer = $('input[name=myRadio]:checked').val();
}
If you have Multiple radio buttons in single form then
var myRadio1 = $('input[name=radioButtonName1]');
var value1 = myRadio1.filter(':checked').val();
var myRadio2 = $('input[name=radioButtonName2]');
var value2 = myRadio2.filter(':checked').val();
This is working for me.
I wrote a jQuery plugin for setting and getting radio-button values. It also respects the "change" event on them.
(function ($) {
function changeRadioButton(element, value) {
var name = $(element).attr("name");
$("[type=radio][name=" + name + "]:checked").removeAttr("checked");
$("[type=radio][name=" + name + "][value=" + value + "]").attr("checked", "checked");
$("[type=radio][name=" + name + "]:checked").change();
}
function getRadioButton(element) {
var name = $(element).attr("name");
return $("[type=radio][name=" + name + "]:checked").attr("value");
}
var originalVal = $.fn.val;
$.fn.val = function(value) {
//is it a radio button? treat it differently.
if($(this).is("[type=radio]")) {
if (typeof value != 'undefined') {
//setter
changeRadioButton(this, value);
return $(this);
} else {
//getter
return getRadioButton(this);
}
} else {
//it wasn't a radio button - let's call the default val function.
if (typeof value != 'undefined') {
return originalVal.call(this, value);
} else {
return originalVal.call(this);
}
}
};
})(jQuery);
Put the code anywhere to enable the addin. Then enjoy! It just overrides the default val function without breaking anything.
You can visit this jsFiddle to try it in action, and see how it works.
Fiddle
$(".Stat").click(function () {
var rdbVal1 = $("input[name$=S]:checked").val();
}
This works fine
$('input[type="radio"][class="className"]:checked').val()
Working Demo
The :checked
selector works for checkboxes
, radio buttons
, and select elements. For select elements only, use the :selected
selector.
API for :checked Selector
To get the value of the selected radio that uses a class:
$('.class:checked').val()
I use this simple script
$('input[name="myRadio"]').on('change', function() {
var radioValue = $('input[name="myRadio"]:checked').val();
alert(radioValue);
});
Use this:
value = $('input[name=button-name]:checked').val();
DEMO : https://jsfiddle.net/ipsjolly/xygr065w/
$(function(){
$("#submit").click(function(){
alert($('input:radio:checked').val());
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr>
<td>Sales Promotion</td>
<td><input type="radio" name="q12_3" value="1">1</td>
<td><input type="radio" name="q12_3" value="2">2</td>
<td><input type="radio" name="q12_3" value="3">3</td>
<td><input type="radio" name="q12_3" value="4">4</td>
<td><input type="radio" name="q12_3" value="5">5</td>
</tr>
</table>
<button id="submit">submit</button>
If you only have 1 set of radio buttons on 1 form, the jQuery code is as simple as this:
$( "input:checked" ).val()
Using $('input[name="radioName"]').filter(":checked").val();
is the best way for me.
Tested, this works
Form
<form id="myForm">
<input type="radio" name="radioName" value="Option1"> Option1
<input type="radio" name="radioName" value="Option2" checked> Option2
<input type="radio" name="radioName" value="Option3"> Option3
</form>
Jquery
$(document).ready(function() {
$('input[name="radioName"]').on('change', function() {
const val = $(this).filter(":checked").val();
alert(val);
})
// First load check
const val = $('input[name="radioName"]').filter(":checked").val();
alert(val);
});
Example here: https://codepen.io/abinhho/pen/mdLrqbX
I've released a library to help with this. Pulls all possible input values, actually, but also includes which radio button was checked. You can check it out at https://github.com/mazondo/formalizedata
It'll give you a js object of the answers, so a form like:
<form>
<input type="radio" name"favorite-color" value="blue" checked> Blue
<input type="radio" name="favorite-color" value="red"> Red
</form>
will give you:
$("form").formalizeData()
{
"favorite-color" : "blue"
}
JQuery to get all the radio buttons in the form and the checked value.
$.each($("input[type='radio']").filter(":checked"), function () {
console.log("Name:" + this.name);
console.log("Value:" + $(this).val());
});
To retrieve all radio buttons values in JavaScript array use following jQuery code :
var values = jQuery('input:checkbox:checked.group1').map(function () {
return this.value;
}).get();
try it-
var radioVal = $("#myform").find("input[type='radio']:checked").val();
console.log(radioVal);
Another way to get it:
$("#myForm input[type=radio]").on("change",function(){
if(this.checked) {
alert(this.value);
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
<span><input type="radio" name="q12_3" value="1">1</span><br>
<span><input type="radio" name="q12_3" value="2">2</span>
</form>
From this question, I came up with an alternate way to access the currently selected input
when you're within a click
event for its respective label. The reason why is because the newly selected input
isn't updated until after its label
's click event.
TL;DR
$('label').click(function() {
var selected = $('#' + $(this).attr('for')).val();
...
});
$(function() {
// this outright does not work properly as explained above
$('#reported label').click(function() {
var query = $('input[name="filter"]:checked').val();
var time = (new Date()).toString();
$('.query[data-method="click event"]').html(query + ' at ' + time);
});
// this works, but fails to update when same label is clicked consecutively
$('#reported input[name="filter"]').on('change', function() {
var query = $('input[name="filter"]:checked').val();
var time = (new Date()).toString();
$('.query[data-method="change event"]').html(query + ' at ' + time);
});
// here is the solution I came up with
$('#reported label').click(function() {
var query = $('#' + $(this).attr('for')).val();
var time = (new Date()).toString();
$('.query[data-method="click event with this"]').html(query + ' at ' + time);
});
});
input[name="filter"] {
display: none;
}
#reported label {
background-color: #ccc;
padding: 5px;
margin: 5px;
border-radius: 5px;
cursor: pointer;
}
.query {
padding: 5px;
margin: 5px;
}
.query:before {
content: "on " attr(data-method)": ";
}
[data-method="click event"] {
color: red;
}
[data-method="change event"] {
color: #cc0;
}
[data-method="click event with this"] {
color: green;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="reported">
<input type="radio" name="filter" id="question" value="questions" checked="checked">
<label for="question">Questions</label>
<input type="radio" name="filter" id="answer" value="answers">
<label for="answer">Answers</label>
<input type="radio" name="filter" id="comment" value="comments">
<label for="comment">Comments</label>
<input type="radio" name="filter" id="user" value="users">
<label for="user">Users</label>
<input type="radio" name="filter" id="company" value="companies">
<label for="company">Companies</label>
<div class="query" data-method="click event"></div>
<div class="query" data-method="change event"></div>
<div class="query" data-method="click event with this"></div>
</form>
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