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I am having an issue while trying to create new kernel for JupyterLab for R + Spark.

Without spark something like this works for me (kernel.json)

{
    "display_name": "R",
    "language": "R",
    "argv": ["R", "--slave", "-e", "IRkernel::main()", "--args", "{connection_file}"]
}

But if I try to replace R with sparkR to make Spark initialise, it fails with:

Fatal error: you must specify '--save', '--no-save' or '--vanilla'.

Passing env var “SPARKR_SUBMIT_ARGS”: “–no-save” did not help also. Does anyone know how to do it properly?

本文标签： Jupyter kernel for RSparkStack Overflow

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