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Assume we have a string like the following :
,34,23,4,5,634,23,12,5,4,3,1234,23,54,,,,,,,123,43,2,3,4,5,3424,,,,,,,,123,,,1234,,,,,,,45,,,56
How can we convert it to the following string with RegExp in Javascript ?
34,23,4,5,634,12,3,1234,54,123,43,2,3424,45,56
Actually, I wanna remove repeated items and first and last ,
char
Assume we have a string like the following :
,34,23,4,5,634,23,12,5,4,3,1234,23,54,,,,,,,123,43,2,3,4,5,3424,,,,,,,,123,,,1234,,,,,,,45,,,56
How can we convert it to the following string with RegExp in Javascript ?
34,23,4,5,634,12,3,1234,54,123,43,2,3424,45,56
Actually, I wanna remove repeated items and first and last ,
char
- 3 uh, where'd the "34" go? – Samuel Edwin Ward Commented Mar 31, 2012 at 22:50
- @SamuelEdwinWard it must have jumped overboard XD anyways, i think RegExp is not the tool for this job. i think you should parse it instead. – Joseph Commented Mar 31, 2012 at 22:51
- I agree that it's not the right tool for the job; something starting with the "split" method on strings is probably the way to go. – Samuel Edwin Ward Commented Mar 31, 2012 at 22:53
- You cannot remove the duplicate numbers solely with a regular expression. – Pointy Commented Mar 31, 2012 at 23:02
- @Samuel Edwin Ward : I forgot it ;) – Mohammad Dayyan Commented Mar 31, 2012 at 23:05
3 Answers
Reset to default 5[edited] To turn these into a set of unique numbers, as you are actually asking for, do this:
function scrapeNumbers(string) {
var seen = {};
var results = [];
string.match(/\d+/g).forEach(function(x) {
if (seen[x]===undefined)
results.push(parseInt(x));
seen[x] = true;
});
return results;
}
Demo:
> scrapeNumbers(',1,22,333,22,,333,4,,,')
[1, 22, 333, 4]
If you had an Array.prototype.unique()
primitive, you could write it like so in one line:
yourString.match(/\d+/g).map(parseBase10).unique()
Unfortunately you need to be a bit verbose and define your own parseBase10 = function(n){return parseInt(n)}
due to this ridiculous hard-to-track-down bug: javascript - Array#map and parseInt
No need for regex. Few tricks
text = ',34,23,4,5,634,23,12,5,4,3,1234,23,54,,,,,,,123,43,2,3,4,5,3424,,,,,,,,123,,,1234,,,,,,,45,,,56';
text = text.replace(/,+/g, ','); //replace two mas with one ma
text = text.replace(/^\s+|\s+$/g,''); //remove the spaces
textarray = text.split(","); // change them into array
textarray = textarray.filter(function(e){ return e.length});
console.log(textarray);
// Now use a function to make the array unique
Array.prototype.unique = function(){
var u = {}, a = [];
for(var i = 0, l = this.length; i < l; ++i){
if(this[i] in u)
continue;
a.push(this[i]);
u[this[i]] = 1;
}
return a;
}
textarray = textarray.unique();
text = textarray.join(','); //bine them back to what you want
console.log(text);
Demo
If you are familier with jQuery
text = text.replace(/,+/g, ',');
text = $.trim(text);
text = $.unique(text.split(",")).filter(function(e){ return e.length}).join(",");
console.log(text);
Demo
This will do it:
function arrIndex(fnd, arr) {
for (var len = arr.length, i = 0; i < len; i++) {
if (i in arr && arr[i] === fnd) {
return i;
}
}
return -1;
}
function scrapeNumbers(str) {
var arr = str.replace(/,+/g, ",").replace(/^,/, "").replace(/,$/, "").split(",");
for (var i = 0, len = arr.length, rtn = []; i < len; i++) {
if (i in arr && arrIndex(arr[i], rtn) == -1) {
rtn.push(arr[i]);
}
}
return rtn.join(",");
}
var str = ",,34,23,4,5,634,23,12,5,4,3,1234,23,54,,,,,,,123,43,2,3,4,5,3424,,,,,,,,123,,,1234,,,,,,,45,,,56,,";
alert(scrapeNumbers(str));
Here is a jsFiddle
Note: I created a custom array.indexOf
function for a better browser support
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