admin管理员组

文章数量:1384497

I'm trying to build tabbed panels where a user can retain at current tab after refresh, updates etc. So, I'm trying to apply this script to my web as a tabbed panel but can't figure out what causes the syntax error. I've been trying to solve the problem for days regarding tabs but can seem to solve it. Btw, I don't use cookies and jquery. I don't use cookies because my friends (my clients) don't use cookies on their terminals. second, I don't use jquery (even though it's better) I prefer php only. please help thank you.

<?php 
 $('ul.tabs').each(function(){
    // For each set of tabs, we want to keep track of
    // which tab is active and its associated content
    var $active, $content, $links = $(this).find('a');
    // If the location.hash matches one of the links, use that as the active tab.
    // If no match is found, use the first link as the initial active tab.
    $active = $($links.filter('[href="'+location.hash+'"]')[0] || $links[0]);
    $active.addClass('active');
    $content = $($active[0].hash);
    // Hide the remaining content
    $links.not($active).each(function () {
      $(this.hash).hide();
    });
    // Bind the click event handler
    $(this).on('click', 'a', function(e){
      // Make the old tab inactive.
      $active.removeClass('active');
      $content.hide();
      // Update the variables with the new link and content
      $active = $(this);
      $content = $(this.hash);
      // Make the tab active.
      $active.addClass('active');
      $content.show();
      // Prevent the anchor's default click action
      e.preventDefault();
    });
  }); ?>
<html>
<head>
</head>
<body>
<ul class='tabs'>
    <li><a href='#tab1'>Tab 1</a></li>
    <li><a href='#tab2'>Tab 2</a></li>
    <li><a href='#tab3'>Tab 3</a></li>
  </ul>
  <div id='tab1'>
    <p>Hi, this is the first tab.</p>
  </div>
  <div id='tab2'>
    <p>This is the 2nd tab.</p>
  </div>
  <div id='tab3'>
    <p>And this is the 3rd tab.</p>
  </div>
  </body>
  </html>

I'm trying to build tabbed panels where a user can retain at current tab after refresh, updates etc. So, I'm trying to apply this script to my web as a tabbed panel but can't figure out what causes the syntax error. I've been trying to solve the problem for days regarding tabs but can seem to solve it. Btw, I don't use cookies and jquery. I don't use cookies because my friends (my clients) don't use cookies on their terminals. second, I don't use jquery (even though it's better) I prefer php only. please help thank you.

<?php 
 $('ul.tabs').each(function(){
    // For each set of tabs, we want to keep track of
    // which tab is active and its associated content
    var $active, $content, $links = $(this).find('a');
    // If the location.hash matches one of the links, use that as the active tab.
    // If no match is found, use the first link as the initial active tab.
    $active = $($links.filter('[href="'+location.hash+'"]')[0] || $links[0]);
    $active.addClass('active');
    $content = $($active[0].hash);
    // Hide the remaining content
    $links.not($active).each(function () {
      $(this.hash).hide();
    });
    // Bind the click event handler
    $(this).on('click', 'a', function(e){
      // Make the old tab inactive.
      $active.removeClass('active');
      $content.hide();
      // Update the variables with the new link and content
      $active = $(this);
      $content = $(this.hash);
      // Make the tab active.
      $active.addClass('active');
      $content.show();
      // Prevent the anchor's default click action
      e.preventDefault();
    });
  }); ?>
<html>
<head>
</head>
<body>
<ul class='tabs'>
    <li><a href='#tab1'>Tab 1</a></li>
    <li><a href='#tab2'>Tab 2</a></li>
    <li><a href='#tab3'>Tab 3</a></li>
  </ul>
  <div id='tab1'>
    <p>Hi, this is the first tab.</p>
  </div>
  <div id='tab2'>
    <p>This is the 2nd tab.</p>
  </div>
  <div id='tab3'>
    <p>And this is the 3rd tab.</p>
  </div>
  </body>
  </html>
Share Improve this question edited Sep 25, 2018 at 15:11 Manikandan C 6981 gold badge9 silver badges22 bronze badges asked Jan 2, 2016 at 3:55 Linda MayLinda May 871 gold badge2 silver badges15 bronze badges 10
  • 3 um, you're running JS inside PHP,. Hence, the error. Those are 2 different animals altogether. – Funk Forty Niner Commented Jan 2, 2016 at 3:56
  • 3 want to see some magic? replace <?php with <script> and ?> with </script> ;-) – Funk Forty Niner Commented Jan 2, 2016 at 3:57
  • This is all jQuery. Right Ralph? @Fred-ii- – Jay Blanchard Commented Jan 2, 2016 at 4:01
  • 1 Si signore Sam @JayBlanchard hey... what're you doing up at this houir? ah, a late night movie I'll bet. The one about where Wile E. gets the Road Runner? – Funk Forty Niner Commented Jan 2, 2016 at 4:03
  • 10-4 Ralph! @Fred-ii- – Jay Blanchard Commented Jan 2, 2016 at 4:04
 |  Show 5 more ments

1 Answer 1

Reset to default 2

You're using Javascript (jQuery to be precise) syntax inside PHP. Hence, the error.

syntax error, unexpected '(', expecting variable (T_VARIABLE) or '$'

  • Those are 2 different animals altogether.

Replace <?php with <script> and ?> with </script> and your code will work.

本文标签: