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What I am doing is: I allocated and initialized two arrays (A, B) in global memory using cudaMalloc() and cudaMemset() and called a kernel with A. The kernel did not do anything with array B, but when I checked B from right after the kernel executed against B from before the kernel is called, there was a huge difference. What happened here?

__global__ void BlockSort(int *A)
{
        //A is an array in global memory. Sort A using BlockRadixSort
        using BlockRadixSort = cub::BlockRadixSort<int, 256, 8>;
        __shared__ typename BlockRadixSort::TempStorage temp_storage;
        int threadKeys[8];
        int seg_idx = gridDim.y * blockIdx.y + blockIdx.x,
            seg_start = RATIO * seg_idx;
        for (int i = 0; i < 8; ++i)
                threadKeys[i] = A[seg_start +
                        8 * (blockDim.y * threadIdx.y + blockIdx.x)];
        BlockRadixSort(temp_storage).Sort(threadKeys);

        for (int i = 0; i < 8; ++i)
                A[seg_start + 8 * (blockDim.y * threadIdx.y + blockIdx.x)]
                        = threadKeys[i];
}


    int* B1;
    B1 = (int*)malloc(sizeof(int) * sz);
    cudaMemcpy(B1, B, sizeof(int) * sz, cudaMemcpyDeviceToHost);

    BlockSort<<<gridDim, blockDim>>>(A); // launch BlockSort with A. Nothing is done to B
    cudaDeviceSynchronize();  // do I really need to synchronize here?
    int* B2;
    B2 = (int*)malloc(sizeof(int) * sz);
    cudaMemcpy(B2, B, sizeof(int) * sz, cudaMemcpyDeviceToHost);
   for (int i = 0; i < sz; ++i)
   {
        if (B1[i] != B2[i])
               printf("at i = %d, B1[%d] = %d, B2[%d] = %d\n",i, i, B1[i], i, B2[i]);
   }

The print messages show B1 and B2 are different at many different indices i.
If I comment out the line launching my BlockSort() kernel, then B1 is same as B2.

Honestly at a loss here. Any help will be appreciated!

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