typescript - Javascript es6 - How to remove duplicates in an array of objects, except the last duplicate one? - Stack Overflow

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I have an array:

var arr = [
  {price: 5, amount: 100},
  {price: 3, amount: 50},
  {price: 10, amount: 20},
  {price: 3, amount: 75},
  {price: 7, amount: 15},
  {price: 3, amount: 65},
  {price: 2, amount: 34}
]

I want to remove the duplicates which has the same price, and only keep the last duplicate one then sort the array based on price from highest to lowest. Here is the result I want:

var result = [
  {price: 10, amount: 20},
  {price : 7, amount: 15},
  {price: 5, amount: 100},
  {price: 3, amount: 65},
  {price: 2, amount: 34}
]

I have an array:

var arr = [
  {price: 5, amount: 100},
  {price: 3, amount: 50},
  {price: 10, amount: 20},
  {price: 3, amount: 75},
  {price: 7, amount: 15},
  {price: 3, amount: 65},
  {price: 2, amount: 34}
]

I want to remove the duplicates which has the same price, and only keep the last duplicate one then sort the array based on price from highest to lowest. Here is the result I want:

var result = [
  {price: 10, amount: 20},
  {price : 7, amount: 15},
  {price: 5, amount: 100},
  {price: 3, amount: 65},
  {price: 2, amount: 34}
]

• javascript
• typescript
• ecmascript-6

Share Improve this question Follow asked Mar 9, 2018 at 8:20 Hoàng NguyễnHoàng Nguyễn 1,18266 gold badges3636 silver badges6060 bronze badges 1

• 1 but there are no duplicated ones on your result... – guijob Commented Mar 9, 2018 at 8:24

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 6

Use reduce to convert it an object first to remove the duplicates and last duplicate should override the previous one

var obj = arr.reduce( ( acc, c ) =>  Object.assign(acc, {[c.price]:c.amount}) , {});

Convert it back to array and sort the same

var output = Object.keys( obj )
              .map( s => ({ price : s, amount : obj[ s ] }) )
              .sort( ( a, b )  => b.price - a.price );

Demo

var arr = [
  {price: 5, amount: 100},
  {price: 3, amount: 50},
  {price: 10, amount: 20},
  {price: 3, amount: 75},
  {price: 7, amount: 15},
  {price: 3, amount: 65},
  {price: 2, amount: 34}
];
var obj = arr.reduce( ( acc, c ) =>  Object.assign(acc, {[c.price]:c.amount}) , {});
var output = Object.keys( obj )
              .map( s => ({ price : s, amount : obj[ s ] }) )
              .sort( ( a, b )  => b.price - a.price );
console.log( output );

I'd use reduceRight and splice to remove duplicates. It doesn't create any useless intermediate objects, just a list of unique prices found along the way:

var arr = [
  {price: 5, amount: 100},
  {price: 3, amount: 50},
  {price: 10, amount: 20},
  {price: 3, amount: 75},
  {price: 7, amount: 15},
  {price: 3, amount: 65},
  {price: 2, amount: 34}
]

arr.reduceRight((acc, obj, i) => {
  acc[obj.price]? arr.splice(i, 1) : acc[obj.price] = true;
  return acc;
}, Object.create(null));

arr.sort((a, b) => b.price - a.price);

console.log(arr)

You can use Array.reduce to aggregate results in an array:

var arr = [
  {price: 5, amount: 100},
  {price: 3, amount: 50},
  {price: 10, amount: 20},
  {price: 3, amount: 75},
  {price: 7, amount: 15},
  {price: 3, amount: 65},
  {price: 2, amount: 34}
]

var results = arr.reduce<{ [price: string] : typeof arr[0] }>((p, e)=> {
    p[e.price] = e
    return p;
}, {});

var resultsAsArray = Object.keys(results)
     .map(k=>results[k])
     .sort((a, b) => b.price - a.price);

You can replace typeof arr[0] with the type of the array items if one is defined.

The idea of the solution is to acumulate the result in an object where the price is the key, if the same key is encountered multiple times, the old value is overwritten to in the end you will have only the last value for a given price.

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