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I've got the following objects using AJAX and stored them in an array:
var homes = [
{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}
];
How do I create a function to sort the objects by the price
property in ascending or descending order using JavaScript only?
I've got the following objects using AJAX and stored them in an array:
var homes = [
{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}
];
How do I create a function to sort the objects by the price
property in ascending or descending order using JavaScript only?
21 revs, 11 users 20%
TomHankers 1
- Related: Sorting arrays numerically by object property value. – Sebastian Simon Commented Apr 10, 2022 at 12:05
27 Answers
Reset to default 2222Sort homes by price in ascending order:
homes.sort(function(a, b) {
return parseFloat(a.price) - parseFloat(b.price);
});
Or after ES6 version:
homes.sort((a, b) => parseFloat(a.price) - parseFloat(b.price));
Some documentation can be found here.
For descending order, you may use
homes.sort((a, b) => parseFloat(b.price) - parseFloat(a.price));
Here's a more flexible version, which allows you to create reusable sort functions, and sort by any field.
const sort_by = (field, reverse, primer) => {
const key = primer ?
function(x) {
return primer(x[field])
} :
function(x) {
return x[field]
};
reverse = !reverse ? 1 : -1;
return function(a, b) {
return a = key(a), b = key(b), reverse * ((a > b) - (b > a));
}
}
//Now you can sort by any field at will...
const homes=[{h_id:"3",city:"Dallas",state:"TX",zip:"75201",price:"162500"},{h_id:"4",city:"Bevery Hills",state:"CA",zip:"90210",price:"319250"},{h_id:"5",city:"New York",state:"NY",zip:"00010",price:"962500"}];
// Sort by price high to low
console.log(homes.sort(sort_by('price', true, parseInt)));
// Sort by city, case-insensitive, A-Z
console.log(homes.sort(sort_by('city', false, (a) => a.toUpperCase()
)));
To sort it you need to create a comparator function taking two arguments. Then call the sort function with that comparator function as follows:
// a and b are object elements of your array
function mycomparator(a,b) {
return parseInt(a.price, 10) - parseInt(b.price, 10);
}
homes.sort(mycomparator);
If you want to sort ascending switch the expressions on each side of the minus sign.
for string sorting in case some one needs it,
const dataArr = {
"hello": [{
"id": 114,
"keyword": "zzzzzz",
"region": "Sri Lanka",
"supportGroup": "administrators",
"category": "Category2"
}, {
"id": 115,
"keyword": "aaaaa",
"region": "Japan",
"supportGroup": "developers",
"category": "Category2"
}]
};
const sortArray = dataArr['hello'];
console.log(sortArray.sort((a, b) => {
if (a.region < b.region)
return -1;
if (a.region > b.region)
return 1;
return 0;
}));
If you have an ES6 compliant browser you can use:
- Arrow functions
- Number() function
- sort() function
The difference between ascending and descending sort order is the sign of the value returned by your compare function:
var ascending = homes.sort((a, b) => Number(a.price) - Number(b.price));
var descending = homes.sort((a, b) => Number(b.price) - Number(a.price));
Here's a working code snippet:
var homes = [{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}];
homes.sort((a, b) => Number(a.price) - Number(b.price));
console.log("ascending", homes);
homes.sort((a, b) => Number(b.price) - Number(a.price));
console.log("descending", homes);
I recommend GitHub: Array sortBy - a best implementation of sortBy
method which uses the Schwartzian transform
But for now we are going to try this approach Gist: sortBy-old.js.
Let's create a method to sort arrays being able to arrange objects by some property.
Creating the sorting function
var sortBy = (function () {
var toString = Object.prototype.toString,
// default parser function
parse = function (x) { return x; },
// gets the item to be sorted
getItem = function (x) {
var isObject = x != null && typeof x === "object";
var isProp = isObject && this.prop in x;
return this.parser(isProp ? x[this.prop] : x);
};
/**
* Sorts an array of elements.
*
* @param {Array} array: the collection to sort
* @param {Object} cfg: the configuration options
* @property {String} cfg.prop: property name (if it is an Array of objects)
* @property {Boolean} cfg.desc: determines whether the sort is descending
* @property {Function} cfg.parser: function to parse the items to expected type
* @return {Array}
*/
return function sortby (array, cfg) {
if (!(array instanceof Array && array.length)) return [];
if (toString.call(cfg) !== "[object Object]") cfg = {};
if (typeof cfg.parser !== "function") cfg.parser = parse;
cfg.desc = !!cfg.desc ? -1 : 1;
return array.sort(function (a, b) {
a = getItem.call(cfg, a);
b = getItem.call(cfg, b);
return cfg.desc * (a < b ? -1 : +(a > b));
});
};
}());
Setting unsorted data
var data = [
{date: "2011-11-14T16:30:43Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T17:22:59Z", quantity: 2, total: 90, tip: 0, type: "Tab"},
{date: "2011-11-14T16:28:54Z", quantity: 1, total: 300, tip: 200, type: "visa"},
{date: "2011-11-14T16:53:41Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T16:48:46Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T17:25:45Z", quantity: 2, total: 200, tip: 0, type: "cash"},
{date: "2011-11-31T17:29:52Z", quantity: 1, total: 200, tip: 100, type: "Visa"},
{date: "2011-11-14T16:58:03Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T16:20:19Z", quantity: 2, total: 190, tip: 100, type: "tab"},
{date: "2011-11-01T16:17:54Z", quantity: 2, total: 190, tip: 100, type: "tab"},
{date: "2011-11-14T17:07:21Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T16:54:06Z", quantity: 1, total: 100, tip: 0, type: "Cash"}
];
Using it
Arrange the array, by "date"
as String
// sort by @date (ascending)
sortBy(data, { prop: "date" });
// expected: first element
// { date: "2011-11-01T16:17:54Z", quantity: 2, total: 190, tip: 100, type: "tab" }
// expected: last element
// { date: "2011-11-31T17:29:52Z", quantity: 1, total: 200, tip: 100, type: "Visa"}
If you want to ignore case sensitive, set the parser
callback:
// sort by @type (ascending) IGNORING case-sensitive
sortBy(data, {
prop: "type",
parser: (t) => t.toUpperCase()
});
// expected: first element
// { date: "2011-11-14T16:54:06Z", quantity: 1, total: 100, tip: 0, type: "Cash" }
// expected: last element
// { date: "2011-11-31T17:29:52Z", quantity: 1, total: 200, tip: 100, type: "Visa" }
If you want to convert the "date"
field as Date
type:
// sort by @date (descending) AS Date object
sortBy(data, {
prop: "date",
desc: true,
parser: (d) => new Date(d)
});
// expected: first element
// { date: "2011-11-31T17:29:52Z", quantity: 1, total: 200, tip: 100, type: "Visa"}
// expected: last element
// { date: "2011-11-01T16:17:54Z", quantity: 2, total: 190, tip: 100, type: "tab" }
Here you can play with the code: jsbin.com/lesebi
Thanks to @Ozesh by his feedback, the issue related to properties with falsy values was fixed.
You want to sort it in Javascript, right? What you want is the sort()
function. In this case you need to write a comparator function and pass it to sort()
, so something like this:
function comparator(a, b) {
return parseInt(a["price"], 10) - parseInt(b["price"], 10);
}
var json = { "homes": [ /* your previous data */ ] };
console.log(json["homes"].sort(comparator));
Your comparator takes one of each of the nested hashes inside the array and decides which one is higher by checking the "price" field.
Use lodash.sortBy, (instructions using commonjs, you can also just put the script include-tag for the cdn at the top of your html)
var sortBy = require('lodash.sortby');
// or
sortBy = require('lodash').sortBy;
Descending order
var descendingOrder = sortBy( homes, 'price' ).reverse();
Ascending order
var ascendingOrder = sortBy( homes, 'price' );
I'm little late for the party but below is my logic for sorting.
function getSortedData(data, prop, isAsc) {
return data.sort((a, b) => {
return (a[prop] < b[prop] ? -1 : 1) * (isAsc ? 1 : -1)
});
}
You can use string1.localeCompare(string2)
for string comparison:
this.myArray.sort((a, b) => {
return a.stringProp.localeCompare(b.stringProp);
});
Note that localeCompare
is case insensitive.
While I am aware that the OP wanted to sort an array of numbers, this question has been marked as the answer for similar questions regarding strings. To that fact, the above answers do not consider sorting an array of text where casing is important. Most answers take the string values and convert them to uppercase/lowercase and then sort one way or another. The requirements that I adhere to are simple:
- Sort alphabetically A-Z
- Uppercase values of the same word should come before lowercase values
- Same letter (A/a, B/b) values should be grouped together
What I expect is [ A, a, B, b, C, c ]
but the answers above return A, B, C, a, b, c
. I actually scratched my head on this for longer than I wanted (which is why I am posting this in hopes that it will help at least one other person). While two users mention the localeCompare
function in the comments for the marked answer, I didn't see that until after I stumbled upon the function while searching around. After reading the String.prototype.localeCompare() documentation I was able to come up with this:
var values = [ "Delta", "charlie", "delta", "Charlie", "Bravo", "alpha", "Alpha", "bravo" ];
var sorted = values.sort((a, b) => a.localeCompare(b, undefined, { caseFirst: "upper" }));
// Result: [ "Alpha", "alpha", "Bravo", "bravo", "Charlie", "charlie", "Delta", "delta" ]
This tells the function to sort uppercase values before lowercase values. The second parameter in the localeCompare
function is to define the locale but if you leave it as undefined
it automatically figures out the locale for you.
This works the same for sorting an array of objects as well:
var values = [
{ id: 6, title: "Delta" },
{ id: 2, title: "charlie" },
{ id: 3, title: "delta" },
{ id: 1, title: "Charlie" },
{ id: 8, title: "Bravo" },
{ id: 5, title: "alpha" },
{ id: 4, title: "Alpha" },
{ id: 7, title: "bravo" }
];
var sorted = values
.sort((a, b) => a.title.localeCompare(b.title, undefined, { caseFirst: "upper" }));
Here is a culmination of all answers above.
Fiddle validation: http://jsfiddle.net/bobberino/4qqk3/
var sortOn = function (arr, prop, reverse, numeric) {
// Ensure there's a property
if (!prop || !arr) {
return arr
}
// Set up sort function
var sort_by = function (field, rev, primer) {
// Return the required a,b function
return function (a, b) {
// Reset a, b to the field
a = primer(a[field]), b = primer(b[field]);
// Do actual sorting, reverse as needed
return ((a < b) ? -1 : ((a > b) ? 1 : 0)) * (rev ? -1 : 1);
}
}
// Distinguish between numeric and string to prevent 100's from coming before smaller
// e.g.
// 1
// 20
// 3
// 4000
// 50
if (numeric) {
// Do sort "in place" with sort_by function
arr.sort(sort_by(prop, reverse, function (a) {
// - Force value to a string.
// - Replace any non numeric characters.
// - Parse as float to allow 0.02 values.
return parseFloat(String(a).replace(/[^0-9.-]+/g, ''));
}));
} else {
// Do sort "in place" with sort_by function
arr.sort(sort_by(prop, reverse, function (a) {
// - Force value to string.
return String(a).toUpperCase();
}));
}
}
A more LINQ like solution:
Array.prototype.orderBy = function (selector, desc = false) {
return [...this].sort((a, b) => {
a = selector(a);
b = selector(b);
if (a == b) return 0;
return (desc ? a > b : a < b) ? -1 : 1;
});
}
Advantages:
- autocompletion for properties
- extends array prototype
- does not change array
- easy to use in method chaining
Usage:
Array.prototype.orderBy = function(selector, desc = false) {
return [...this].sort((a, b) => {
a = selector(a);
b = selector(b);
if (a == b) return 0;
return (desc ? a > b : a < b) ? -1 : 1;
});
};
var homes = [{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}];
let sorted_homes = homes.orderBy(h => parseFloat(h.price));
console.log("sorted by price", sorted_homes);
let sorted_homes_desc = homes.orderBy(h => h.city, true);
console.log("sorted by City descending", sorted_homes_desc);
You can use the JavaScript sort
method with a callback function:
function compareASC(homeA, homeB)
{
return parseFloat(homeA.price) - parseFloat(homeB.price);
}
function compareDESC(homeA, homeB)
{
return parseFloat(homeB.price) - parseFloat(homeA.price);
}
// Sort ASC
homes.sort(compareASC);
// Sort DESC
homes.sort(compareDESC);
For sorting a array you must define a comparator function. This function always be different on your desired sorting pattern or order(i.e. ascending or descending).
Let create some functions that sort an array ascending or descending and that contains object or string or numeric values.
function sorterAscending(a,b) {
return a-b;
}
function sorterDescending(a,b) {
return b-a;
}
function sorterPriceAsc(a,b) {
return parseInt(a['price']) - parseInt(b['price']);
}
function sorterPriceDes(a,b) {
return parseInt(b['price']) - parseInt(b['price']);
}
Sort numbers (alphabetically and ascending):
var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.sort();
Sort numbers (alphabetically and descending):
var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.sort();
fruits.reverse();
Sort numbers (numerically and ascending):
var points = [40,100,1,5,25,10];
points.sort(sorterAscending());
Sort numbers (numerically and descending):
var points = [40,100,1,5,25,10];
points.sort(sorterDescending());
As above use sorterPriceAsc and sorterPriceDes method with your array with desired key.
homes.sort(sorterPriceAsc()) or homes.sort(sorterPriceDes())
While it is a bit of an overkill for just sorting a single array, this prototype function allows to sort Javascript arrays by any key, in ascending or descending order, including nested keys, using dot
syntax.
(function(){
var keyPaths = [];
var saveKeyPath = function(path) {
keyPaths.push({
sign: (path[0] === '+' || path[0] === '-')? parseInt(path.shift()+1) : 1,
path: path
});
};
var valueOf = function(object, path) {
var ptr = object;
for (var i=0,l=path.length; i<l; i++) ptr = ptr[path[i]];
return ptr;
};
var comparer = function(a, b) {
for (var i = 0, l = keyPaths.length; i < l; i++) {
aVal = valueOf(a, keyPaths[i].path);
bVal = valueOf(b, keyPaths[i].path);
if (aVal > bVal) return keyPaths[i].sign;
if (aVal < bVal) return -keyPaths[i].sign;
}
return 0;
};
Array.prototype.sortBy = function() {
keyPaths = [];
for (var i=0,l=arguments.length; i<l; i++) {
switch (typeof(arguments[i])) {
case "object": saveKeyPath(arguments[i]); break;
case "string": saveKeyPath(arguments[i].match(/[+-]|[^.]+/g)); break;
}
}
return this.sort(comparer);
};
})();
Usage:
var data = [
{ name: { first: 'Josh', last: 'Jones' }, age: 30 },
{ name: { first: 'Carlos', last: 'Jacques' }, age: 19 },
{ name: { first: 'Carlos', last: 'Dante' }, age: 23 },
{ name: { first: 'Tim', last: 'Marley' }, age: 9 },
{ name: { first: 'Courtney', last: 'Smith' }, age: 27 },
{ name: { first: 'Bob', last: 'Smith' }, age: 30 }
]
data.sortBy('age'); // "Tim Marley(9)", "Carlos Jacques(19)", "Carlos Dante(23)", "Courtney Smith(27)", "Josh Jones(30)", "Bob Smith(30)"
Sorting by nested properties with dot-syntax or array-syntax:
data.sortBy('name.first'); // "Bob Smith(30)", "Carlos Dante(23)", "Carlos Jacques(19)", "Courtney Smith(27)", "Josh Jones(30)", "Tim Marley(9)"
data.sortBy(['name', 'first']); // "Bob Smith(30)", "Carlos Dante(23)", "Carlos Jacques(19)", "Courtney Smith(27)", "Josh Jones(30)", "Tim Marley(9)"
Sorting by multiple keys:
data.sortBy('name.first', 'age'); // "Bob Smith(30)", "Carlos Jacques(19)", "Carlos Dante(23)", "Courtney Smith(27)", "Josh Jones(30)", "Tim Marley(9)"
data.sortBy('name.first', '-age'); // "Bob Smith(30)", "Carlos Dante(23)", "Carlos Jacques(19)", "Courtney Smith(27)", "Josh Jones(30)", "Tim Marley(9)"
You can fork the repo: https://github.com/eneko/Array.sortBy
For a normal array of elements values only:
function sortArrayOfElements(arrayToSort) {
function compareElements(a, b) {
if (a < b)
return -1;
if (a > b)
return 1;
return 0;
}
return arrayToSort.sort(compareElements);
}
e.g. 1:
var array1 = [1,2,545,676,64,2,24]
output : [1, 2, 2, 24, 64, 545, 676]
var array2 = ["v","a",545,676,64,2,"24"]
output: ["a", "v", 2, "24", 64, 545, 676]
For an array of objects:
function sortArrayOfObjects(arrayToSort, key) {
function compareObjects(a, b) {
if (a[key] < b[key])
return -1;
if (a[key] > b[key])
return 1;
return 0;
}
return arrayToSort.sort(compareObjects);
}
e.g. 1: var array1= [{"name": "User4", "value": 4},{"name": "User3", "value": 3},{"name": "User2", "value": 2}]
output : [{"name": "User2", "value": 2},{"name": "User3", "value": 3},{"name": "User4", "value": 4}]
If you use Underscore.js, try sortBy:
// price is of an integer type
_.sortBy(homes, "price");
// price is of a string type
_.sortBy(homes, function(home) {return parseInt(home.price);});
Here is a slightly modified version of elegant implementation from the book "JavaScript: The Good Parts".
NOTE: This version of by
is stable. It preserves the order of the first sort while performing the next chained sort.
I have added isAscending
parameter to it. Also converted it to ES6
standards and "newer" good parts as recommended by the author.
You can sort ascending as well as descending and chain sort by multiple properties.
const by = function (name, minor, isAscending=true) {
const reverseMutliplier = isAscending ? 1 : -1;
return function (o, p) {
let a, b;
let result;
if (o && p && typeof o === "object" && typeof p === "object") {
a = o[name];
b = p[name];
if (a === b) {
return typeof minor === 'function' ? minor(o, p) : 0;
}
if (typeof a === typeof b) {
result = a < b ? -1 : 1;
} else {
result = typeof a < typeof b ? -1 : 1;
}
return result * reverseMutliplier;
} else {
throw {
name: "Error",
message: "Expected an object when sorting by " + name
};
}
};
};
let s = [
{first: 'Joe', last: 'Besser'},
{first: 'Moe', last: 'Howard'},
{first: 'Joe', last: 'DeRita'},
{first: 'Shemp', last: 'Howard'},
{first: 'Larry', last: 'Fine'},
{first: 'Curly', last: 'Howard'}
];
// Sort by: first ascending, last ascending
s.sort(by("first", by("last")));
console.log("Sort by: first ascending, last ascending: ", s); // "[
// {"first":"Curly","last":"Howard"},
// {"first":"Joe","last":"Besser"}, <======
// {"first":"Joe","last":"DeRita"}, <======
// {"first":"Larry","last":"Fine"},
// {"first":"Moe","last":"Howard"},
// {"first":"Shemp","last":"Howard"}
// ]
// Sort by: first ascending, last descending
s.sort(by("first", by("last", 0, false)));
console.log("sort by: first ascending, last descending: ", s); // "[
// {"first":"Curly","last":"Howard"},
// {"first":"Joe","last":"DeRita"}, <========
// {"first":"Joe","last":"Besser"}, <========
// {"first":"Larry","last":"Fine"},
// {"first":"Moe","last":"Howard"},
// {"first":"Shemp","last":"Howard"}
// ]
Create a function and sort based on the input using below code
var homes = [{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}];
function sortList(list,order){
if(order=="ASC"){
return list.sort((a,b)=>{
return parseFloat(a.price) - parseFloat(b.price);
})
}
else{
return list.sort((a,b)=>{
return parseFloat(b.price) - parseFloat(a.price);
});
}
}
sortList(homes,'DESC');
console.log(homes);
For sort on multiple array object field.
Enter your field name in arrprop
array like ["a","b","c"]
then pass in second parameter arrsource
actual source we want to sort.
function SortArrayobject(arrprop,arrsource){
arrprop.forEach(function(i){
arrsource.sort(function(a,b){
return ((a[i] < b[i]) ? -1 : ((a[i] > b[i]) ? 1 : 0));
});
});
return arrsource;
}
You will need two function
function desc(a, b) {
return b < a ? -1 : b > a ? 1 : b >= a ? 0 : NaN;
}
function asc(a, b) {
return a < b ? -1 : a > b ? 1 : a >= b ? 0 : NaN;
}
Then you can apply this to any object property:
data.sort((a, b) => desc(parseFloat(a.price), parseFloat(b.price)));
let data = [
{label: "one", value:10},
{label: "two", value:5},
{label: "three", value:1},
];
// sort functions
function desc(a, b) {
return b < a ? -1 : b > a ? 1 : b >= a ? 0 : NaN;
}
function asc(a, b) {
return a < b ? -1 : a > b ? 1 : a >= b ? 0 : NaN;
}
// DESC
data.sort((a, b) => desc(a.value, b.value));
document.body.insertAdjacentHTML(
'beforeend',
'<strong>DESCending sorted</strong><pre>' + JSON.stringify(data) +'</pre>'
);
// ASC
data.sort((a, b) => asc(a.value, b.value));
document.body.insertAdjacentHTML(
'beforeend',
'<strong>ASCending sorted</strong><pre>' + JSON.stringify(data) +'</pre>'
);
Hi after reading this article, I made a sortComparator for my needs, with the functionality to compare more than one json attributes, and i want to share it with you.
This solution compares only strings in ascending order, but the solution can be easy extended for each attribute to support: reverse ordering, other data types, to use locale, casting etc
var homes = [{
"h_id": "3",
"city": "Dallas",
"state": "TX",
"zip": "75201",
"price": "162500"
}, {
"h_id": "4",
"city": "Bevery Hills",
"state": "CA",
"zip": "90210",
"price": "319250"
}, {
"h_id": "5",
"city": "New York",
"state": "NY",
"zip": "00010",
"price": "962500"
}];
// comp = array of attributes to sort
// comp = ['attr1', 'attr2', 'attr3', ...]
function sortComparator(a, b, comp) {
// Compare the values of the first attribute
if (a[comp[0]] === b[comp[0]]) {
// if EQ proceed with the next attributes
if (comp.length > 1) {
return sortComparator(a, b, comp.slice(1));
} else {
// if no more attributes then return EQ
return 0;
}
} else {
// return less or great
return (a[comp[0]] < b[comp[0]] ? -1 : 1)
}
}
// Sort array homes
homes.sort(function(a, b) {
return sortComparator(a, b, ['state', 'city', 'zip']);
});
// display the array
homes.forEach(function(home) {
console.log(home.h_id, home.city, home.state, home.zip, home.price);
});
and the result is
$ node sort
4 Bevery Hills CA 90210 319250
5 New York NY 00010 962500
3 Dallas TX 75201 162500
and another sort
homes.sort(function(a, b) {
return sortComparator(a, b, ['city', 'zip']);
});
with result
$ node sort
4 Bevery Hills CA 90210 319250
3 Dallas TX 75201 162500
5 New York NY 00010 962500
function compareValues(key, order = 'asc') {
return function innerSort(a, b) {
if (!a.hasOwnProperty(key) || !b.hasOwnProperty(key)) {
// property doesn't exist on either object
return 0;
}
const varA = (typeof a[key] === 'string')
? a[key].toUpperCase() : a[key];
const varB = (typeof b[key] === 'string')
? b[key].toUpperCase() : b[key];
let comparison = 0;
if (varA > varB) {
comparison = 1;
} else if (varA < varB) {
comparison = -1;
}
return (
(order === 'desc') ? (comparison * -1) : comparison
);
};
}
http://yazilimsozluk.com/sort-array-in-javascript-by-asc-or-desc
I recently wrote a universal function to manage this for you if you want to use it.
/**
* Sorts an object into an order
*
* @require jQuery
*
* @param object Our JSON object to sort
* @param type Only alphabetical at the moment
* @param identifier The array or object key to sort by
* @param order Ascending or Descending
*
* @returns Array
*/
function sortItems(object, type, identifier, order){
var returnedArray = [];
var emptiesArray = []; // An array for all of our empty cans
// Convert the given object to an array
$.each(object, function(key, object){
// Store all of our empty cans in their own array
// Store all other objects in our returned array
object[identifier] == null ? emptiesArray.push(object) : returnedArray.push(object);
});
// Sort the array based on the type given
switch(type){
case 'alphabetical':
returnedArray.sort(function(a, b){
return (a[identifier] == b[identifier]) ? 0 : (
// Sort ascending or descending based on order given
order == 'asc' ? a[identifier] > b[identifier] : a[identifier] < b[identifier]
) ? 1 : -1;
});
break;
default:
}
// Return our sorted array along with the empties at the bottom depending on sort order
return order == 'asc' ? returnedArray.concat(emptiesArray) : emptiesArray.concat(returnedArray);
}
You can create a function to sort the objects in the homes array by the price property in either ascending or descending order using JavaScript's sort() method while passing an optional order parameter.
Here is how you can do it:
var homes = [
{ "h_id": "3", "city": "Dallas", "state": "TX", "zip": "75201", "price": "162500" },
{ "h_id": "4", "city": "Beverly Hills", "state": "CA", "zip": "90210", "price": "319250" },
{ "h_id": "5", "city": "New York", "state": "NY", "zip": "00010", "price": "962500" }
];
function sortHomesByPrice(homesArray, order = 'ascending') {
return homesArray.sort((a, b) =>
order === 'ascending' ? parseFloat(a.price) - parseFloat(b.price) : parseFloat(b.price) - parseFloat(a.price)
);
}
console.log("Ascending Order:", sortHomesByPrice(homes, 'ascending'));
console.log("Descending Order:", sortHomesByPrice(homes, 'descending'));
You can use the below approach if you don't want to use any sort()
method
function sortObj(obj) {
let numArr = []; //the array which just includes prices as Number
let sortedObj = [];
obj.map((x) => {
numArr.push(Number(x["price"]));
});
while (numArr.length > 0) {
let minIndex = numArr.indexOf(Math.min(...numArr)); //the index of cheapest home in the obj
numArr.splice(minIndex, 1);
sortedObj.push(obj.splice(minIndex, 1)); // splicing cheapest home from Homes Array to sortedObj Array.
}
console.log(sortedObj);
}
var homes = [
{
h_id: "3",
city: "Dallas",
state: "TX",
zip: "75201",
price: "162500",
},
{
h_id: "4",
city: "Bevery Hills",
state: "CA",
zip: "90210",
price: "319250",
},
{
h_id: "5",
city: "New York",
state: "NY",
zip: "00010",
price: "962500",
},
];
sortObj(homes);
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